(2/3)y-(1/3)=(4/9)y^2

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Solution for (2/3)y-(1/3)=(4/9)y^2 equation: 


y in (-oo:+oo)

(2/3)*y-(1/3) = (4/9)*y^2 // - (4/9)*y^2

(2/3)*y-((4/9)*y^2)-(1/3) = 0

(-4/9)*y^2+(2/3)*y-1/3 = 0

2/3*y-4/9*y^2-1/3 = 0

DELTA = (2/3)^2-(-4/9*(-1/3)*4)

DELTA = -4/27

DELTA < 0

y belongs to the empty set

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